Free O Level Chemistry 5070 Study Guide — Edvia College
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O Level Chemistry 5070 — every topic, free.

A complete study guide for Cambridge O Level Chemistry 5070, mapped to all 49 sub-topics of the official syllabus for exams in 2026–2028, including the qualitative analysis tables and a full section on the practical skills worth 20% of your grade.

How to use it: chemistry splits into three kinds of marks — recall (definitions, tests, colours), calculation (moles, almost always), and explanation (in terms of particles, bonding or electrons). Each unit here gives you all three, then a skill check. Attempt it before opening the answer.

CAIE 5070 · exams 2026–202849 syllabus units12 topicsFull ion & gas testsPractical/ATP included
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The three papers

PaperFormatTime / marksWeight
Paper 1 — Multiple Choice40 four-option multiple-choice questions1 hour · 40 marks30%
Paper 2 — TheoryShort-answer and structured questions1 h 45 min · 80 marks50%
Paper 3 — Practical Test orExperiments carried out in a laboratory1 h 30 min · 40 marks20%
Paper 4 — Alternative to PracticalWritten questions on experiments; no lab work1 hour · 40 marks20%

Assessment objectives: AO1 Knowledge with understanding, AO2 Handling information and problem-solving, AO3 Experimental skills (20% — Papers 3 and 4 test this alone).

What you are given in the exam: a Periodic Table (so you never need to memorise relative atomic masses — look them up), and for Papers 3 and 4 only, the Notes for use in qualitative analysis (the ion and gas test tables). You are not given those tables in Paper 2 — so the tests must be memorised for the theory paper even though they are handed to you in the practical one. That asymmetry catches people out every year.
Learn these — not given in Paper 2

Qualitative analysis: every test in one place

These tables are the single densest source of marks in the subject. Provided to you in Papers 3 and 4, but required from memory in Paper 2 — and they appear in nearly every theory paper.

Tests for gases

GasTest and result
Ammonia, NH3Turns damp red litmus paper blue
Carbon dioxide, CO2Turns limewater milky
Chlorine, Cl2Bleaches damp litmus paper
Hydrogen, H2'Pops' with a lighted splint
Oxygen, O2Relights a glowing splint
Sulfur dioxide, SO2Turns acidified aqueous potassium manganate(VII) from purple to colourless

Tests for aqueous cations (metal ions)

Add the reagent a little at a time, then in excess — the behaviour in excess is what distinguishes several of these.

CationWith aqueous sodium hydroxideWith aqueous ammonia
Aluminium, Al3+White ppt., soluble in excess giving a colourless solutionWhite ppt., insoluble in excess
Ammonium, NH4+Ammonia produced on warming
Calcium, Ca2+White ppt., insoluble in excessNo ppt. or very slight white ppt.
Chromium(III), Cr3+Green ppt., soluble in excessGreen ppt., insoluble in excess
Copper(II), Cu2+Light blue ppt., insoluble in excessLight blue ppt., soluble in excess giving a dark blue solution
Iron(II), Fe2+Green ppt., insoluble in excess; turns brown near the surface on standingGreen ppt., insoluble in excess; turns brown near the surface on standing
Iron(III), Fe3+Red-brown ppt., insoluble in excessRed-brown ppt., insoluble in excess
Zinc, Zn2+White ppt., soluble in excess giving a colourless solutionWhite ppt., soluble in excess giving a colourless solution
How to tell the tricky ones apart
  • Three white precipitates — Al3+, Ca2+, Zn2+. Use both reagents: Ca2+ is insoluble in excess NaOH; Al3+ dissolves in excess NaOH but not in excess ammonia; Zn2+ dissolves in both.
  • Fe2+ vs Fe3+ — green versus red-brown. Straightforward, but write "red-brown", not just "brown".
  • Cu2+ — the only one giving a dark blue solution in excess ammonia.

Tests for anions

AnionTestResult
Carbonate, CO32−Add dilute acid, then test the gasEffervescence; CO2 turns limewater milky
Chloride, Cl (in solution)Acidify with dilute nitric acid, add aqueous silver nitrateWhite ppt.
Bromide, Br (in solution)Acidify with dilute nitric acid, add aqueous silver nitrateCream ppt.
Iodide, I (in solution)Acidify with dilute nitric acid, add aqueous silver nitrateYellow ppt.
Nitrate, NO3 (in solution)Add aqueous sodium hydroxide, then aluminium foil; warm carefullyAmmonia produced
Sulfate, SO42− (in solution)Acidify with dilute nitric acid, add aqueous barium nitrateWhite ppt.
Sulfite, SO32−Add a small volume of acidified aqueous potassium manganate(VII)Purple → colourless
Forgetting to acidify with dilute nitric acid first in the halide and sulfate tests. Without it, carbonate ions present would also give a white precipitate, so the test would not be valid. Examiners award a mark specifically for that step.

Flame tests for metal ions

Metal ionFlame colourMetal ionFlame colour
Lithium, Li+RedCalcium, Ca2+Orange-red
Sodium, Na+YellowBarium, Ba2+Light green
Potassium, K+LilacCopper(II), Cu2+Blue-green

Test for water: anhydrous copper(II) sulfate turns white → blue; anhydrous cobalt(II) chloride turns blue → pink. To show water is pure, check it boils at exactly 100 °C and freezes at exactly 0 °C at standard atmospheric pressure.

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Study planner & progress

All 49 syllabus units plus the practical skills section. Tick one when you can do a past-paper question on it unaided. Your ticks are saved on this device only — nothing is sent anywhere, and there is no account to create.

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Topic 1 · 2 units

States of matter

1.1Solids, liquids and gases

SolidLiquidGas
ArrangementRegular, closely packedRandomly arranged, close togetherRandomly arranged, far apart
MovementVibrate about fixed positionsMove around each otherMove rapidly and randomly
Forces of attractionStrongWeakerVery weak / negligible
PropertiesFixed shape and volume; cannot be compressedFixed volume, takes shape of containerNo fixed shape or volume; easily compressed

Changes of state and their names: melting (s→l), freezing (l→s), boiling/evaporation (l→g), condensation (g→l), sublimation (s→g directly).

Explaining any change of stateAlways mention energy, forces of attraction and arrangement/movement: "On heating, particles gain energy and vibrate more; at the melting point they have enough energy to overcome the forces of attraction holding them in fixed positions, so the regular structure breaks down and the solid melts."
Skill check: Explain why a gas can be compressed but a liquid cannot.
Solution: In a gas the particles are far apart with large spaces between them, so they can be pushed much closer together. In a liquid the particles are already touching with very little space between them, so there is nothing to compress.

1.2Diffusion

DefinitionDiffusion is the net movement of particles from a region of higher concentration to a region of lower concentration, due to the random movement of particles.

Diffusion is faster at higher temperature (particles have more kinetic energy and move faster) and faster for lighter particles — at the same temperature, a gas with a lower relative molecular mass diffuses more quickly.

The classic demonstration: cotton wool soaked in concentrated ammonia solution at one end of a glass tube and concentrated hydrochloric acid at the other. A white ring of ammonium chloride forms nearer the hydrochloric acid end, because NH3 (Mr = 17) is lighter than HCl (Mr = 36.5) and so diffuses faster.

Skill check: Two gases, X (Mr = 32) and Y (Mr = 71), are released at the same time from opposite ends of a tube. Which travels further before they meet?
Solution: X, because it has the smaller relative molecular mass, so its particles move faster at the same temperature and it diffuses more quickly.
Topic 2 · 7 units

Atoms, elements and compounds

Bonding is the topic that explains everything later — why some substances conduct, why melting points differ, why ionic solids dissolve. Structure your answers around the type of particle, the forces between them, and what happens to those forces.

2.1Elements, compounds and mixtures

  • Element: a substance made of only one type of atom; cannot be broken down chemically.
  • Compound: two or more different elements chemically combined in a fixed ratio; has properties different from its elements and can only be separated chemically.
  • Mixture: two or more substances not chemically combined; keeps the properties of its components and can be separated by physical means.

2.2Atomic structure and the Periodic Table  2.3Isotopes

ParticleRelative massRelative chargeLocation
Proton1+1Nucleus
Neutron10Nucleus
Electron1/1840 (negligible)−1Shells around the nucleus
Key numbersProton number (atomic number) = number of protons = number of electrons in a neutral atom, and it defines the element.
Nucleon number (mass number) = protons + neutrons. Neutrons = nucleon number − proton number.

Electronic configuration: shells fill 2, 8, 8… (e.g. chlorine, 17 electrons → 2,8,7). In the Periodic Table, the group number equals the number of outer-shell electrons and the period number equals the number of occupied shells. Elements in the same group have similar chemical properties because they have the same number of outer electrons.

IsotopesIsotopes are atoms of the same element with the same proton number but different numbers of neutrons. They have identical chemical properties (same electronic configuration) but slightly different physical properties such as density.
Skill check: An atom has 19 protons and 20 neutrons. Give its nucleon number, electronic configuration and group.
Solution: Nucleon number = 19 + 20 = 39. 19 electrons → 2,8,8,1. One outer electron → Group I (it is potassium), in Period 4 because it has four occupied shells.

2.4Ions and ionic bonds

DefinitionIonic bonding is the strong electrostatic attraction between oppositely charged ions, formed when a metal transfers electrons to a non-metal so that both achieve a full outer shell.

Metals lose electrons to form positive ions (cations); non-metals gain electrons to form negative ions (anions). Group I → 1+, Group II → 2+, Group VI → 2−, Group VII → 1−.

Property of ionic compoundsExplanation
High melting and boiling pointsGiant ionic lattice; a large amount of energy is needed to overcome the strong electrostatic forces between oppositely charged ions
Do not conduct when solidIons are held in fixed positions and cannot move
Conduct when molten or in aqueous solutionIons are now free to move and carry charge
Usually soluble in waterWater molecules can separate and surround the ions
Saying ionic compounds conduct "because electrons move". They do not — conduction in an ionic liquid or solution is due to moving ions. Electrons are the charge carriers in metals only.

2.5Simple molecules and covalent bonds  2.6Giant covalent structures

DefinitionA covalent bond is formed when a pair of electrons is shared between two non-metal atoms, so that each achieves a full outer shell.

Simple molecular substances (H2, Cl2, H2O, CH4, CO2) have low melting and boiling points: the covalent bonds within molecules are strong, but the intermolecular forces between molecules are weak and only these need to be overcome when melting or boiling. They do not conduct electricity — there are no free electrons or ions.

Writing that "the covalent bonds are broken when the substance melts". They are not. Only the weak intermolecular forces between molecules are overcome. Stating this correctly is worth a mark almost every series.
DiamondGraphiteSilicon(IV) oxide
BondingEach carbon bonded to 4 others, tetrahedralEach carbon bonded to 3 others in layers, one delocalised electron per atomEach Si bonded to 4 O, each O to 2 Si
HardnessVery hard — rigid 3D network of strong bondsSoft/slippery — weak forces between layers let them slideHard
Conducts?No — no free electronsYes — delocalised electrons move along layersNo
UsesCutting tools, jewelleryPencil "lead", lubricant, electrodesSand, glass, abrasives

All giant covalent structures have very high melting points because many strong covalent bonds must be broken.

Skill check: Diamond and graphite are both pure carbon. Explain why graphite conducts electricity and diamond does not.
Solution: In graphite each carbon atom forms only three covalent bonds, leaving one electron per atom delocalised and free to move between the layers, so charge can flow. In diamond each carbon forms four covalent bonds, so all outer electrons are used in bonding and none are free to move.

2.7Metallic bonding

DefinitionMetallic bonding is the electrostatic attraction between a lattice of positive metal ions and a 'sea' of delocalised electrons.
  • Good conductors of electricity and heat — delocalised electrons are free to move and carry charge/energy.
  • Malleable and ductile — the layers of positive ions can slide over each other without breaking the metallic bonding, because the delocalised electrons keep holding the lattice together.
  • High melting points — strong attraction between the ions and the delocalised electrons.
Topic 3 · 3 units

Stoichiometry

The calculation engine of the whole subject. Almost every numerical mark in Paper 2 comes from here, and the method is nearly always the same three steps: convert to moles, use the equation ratio, convert back.

3.1Formulae

Write formulae by balancing the charges so the compound is neutral. Common ions to know:

1+2+3+1−2−3−
Na+, K+, Li+, Ag+, NH4+, H+Mg2+, Ca2+, Zn2+, Cu2+, Fe2+, Pb2+, Ba2+Al3+, Fe3+, Cr3+Cl, Br, I, OH, NO3, HCO3O2−, S2−, CO32−, SO42−N3−, PO43−

Balancing equations: change only the big numbers in front (coefficients), never the small subscripts inside a formula. Include state symbols where asked: (s) solid, (l) liquid, (g) gas, (aq) aqueous.

Worked example

Balance: Al + O2 → Al2O3

  1. Balance O: the least common multiple of 2 and 3 is 6 → 3O2 on the left, 2Al2O3 on the right
  2. Now Al: 4 on the right, so 4Al on the left
  3. 4Al + 3O2 → 2Al2O3 (Al: 4 = 4 ✓, O: 6 = 6 ✓)

3.2Relative masses  3.3The mole and the Avogadro constant

Definitions and constantsRelative atomic mass (Ar) — the average mass of an atom compared with 1/12 the mass of a carbon-12 atom. Relative molecular / formula mass (Mr) — the sum of the Ar values in the formula.
The mole (mol) is the unit of amount of substance; one mole contains 6.02 × 10²³ particles — the Avogadro constant.
The five relationships — memorise these
amount (mol) = mass (g) ÷ molar mass (g/mol)
number of particles = amount (mol) × 6.02 × 10²³
volume of gas at r.t.p. (dm³) = amount (mol) × 24
concentration (mol/dm³) = amount (mol) ÷ volume (dm³)
volume in dm³ = volume in cm³ ÷ 1000
The universal three-step method1. Convert what you are given into moles. 2. Use the ratio in the balanced equation to find moles of what you want. 3. Convert those moles into the units asked for (mass, volume or concentration).
Worked example — reacting masses and gas volume

25.0 g of calcium carbonate is heated: CaCO3 → CaO + CO2. Find the mass of calcium oxide and the volume of carbon dioxide at r.t.p. (Ar: Ca 40, C 12, O 16)

  1. Mr(CaCO3) = 40 + 12 + (3 × 16) = 100
  2. Moles CaCO3 = 25.0 ÷ 100 = 0.250 mol
  3. Ratio is 1 : 1 : 1, so moles CaO = 0.250 and moles CO2 = 0.250
  4. Mr(CaO) = 40 + 16 = 56, so mass = 0.250 × 56 = 14.0 g
  5. Volume CO2 = 0.250 × 24 = 6.00 dm³
Worked example — titration

25.0 cm³ of sodium hydroxide solution is exactly neutralised by 20.0 cm³ of 0.100 mol/dm³ hydrochloric acid. Find the concentration of the sodium hydroxide.
NaOH + HCl → NaCl + H2O

  1. Moles HCl = concentration × volume = 0.100 × (20.0 ÷ 1000) = 0.00200 mol
  2. Ratio 1 : 1, so moles NaOH = 0.00200 mol
  3. Concentration NaOH = 0.00200 ÷ (25.0 ÷ 1000) = 0.0800 mol/dm³
  4. In g/dm³: × Mr(NaOH) = 40 → 0.0800 × 40 = 3.20 g/dm³
Worked example — empirical and molecular formula

A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass, and has Mr = 180. Find its empirical and molecular formulae.

  1. Divide each percentage by Ar: C 40.0/12 = 3.33; H 6.7/1 = 6.7; O 53.3/16 = 3.33
  2. Divide by the smallest (3.33): C 1 : H 2 : O 1
  3. Empirical formula = CH2O (empirical mass = 12 + 2 + 16 = 30)
  4. 180 ÷ 30 = 6, so molecular formula = C6H12O6
Worked example — percentage yield and purity

A reaction should theoretically produce 8.00 g of product but only 6.00 g is obtained. Find the percentage yield. Separately, find the percentage of calcium by mass in CaCO3.

  1. % yield = (actual ÷ theoretical) × 100 = (6.00 ÷ 8.00) × 100 = 75.0%
  2. % Ca = (40 ÷ 100) × 100 = 40.0%
Limiting reactantConvert both reactants to moles, divide each by its coefficient in the equation, and the smaller value is the limiting reactant. All yield calculations must be based on that one — the other is in excess.
Forgetting to convert cm³ to dm³ (divide by 1000) in concentration work. This single slip turns an otherwise perfect titration answer into one that is out by a factor of 1000.
Skill check: What volume of hydrogen at r.t.p. is produced when 0.240 g of magnesium reacts completely with excess hydrochloric acid? (Ar Mg = 24) Mg + 2HCl → MgCl2 + H2
Solution: Moles Mg = 0.240 ÷ 24 = 0.0100 mol. Ratio Mg : H2 is 1 : 1, so moles H2 = 0.0100 mol. Volume = 0.0100 × 24 = 0.240 dm³ (240 cm³).
Topic 4 · 2 units

Electrochemistry

4.1Electrolysis

DefinitionElectrolysis is the decomposition of an ionic compound, when molten or in aqueous solution, by the passage of an electric current.
Anode = positive electrode (attracts anions); cathode = negative electrode (attracts cations). The electrolyte is the molten or aqueous substance being decomposed.
How charge movesElectrons flow through the external circuit (wires) only. Inside the electrolyte, charge is carried by moving ions. At the cathode positive ions gain electrons (reduction); at the anode negative ions lose electrons (oxidation). Remember OIL RIG — Oxidation Is Loss, Reduction Is Gain (of electrons).
Electrolyte (inert electrodes)At the cathode (−)At the anode (+)
Molten lead(II) bromideLead — a silvery liquid forms
Pb2+ + 2e → Pb
Bromine — red-brown vapour
2Br → Br2 + 2e
Concentrated aqueous sodium chlorideHydrogen — gas bubbles, 'pops'
2H+ + 2e → H2
Chlorine — pale green gas, bleaches litmus
2Cl → Cl2 + 2e
Dilute sulfuric acidHydrogen
2H+ + 2e → H2
Oxygen — relights a glowing splint
4OH → O2 + 2H2O + 4e

In dilute sulfuric acid, hydrogen is produced at twice the volume of oxygen — the classic Hofmann voltameter observation.

Saying electrons travel through the electrolyte. They do not — only ions move in the electrolyte. Electrons move only through the wires and electrodes.
Skill check: Why does solid lead(II) bromide not conduct electricity, but molten lead(II) bromide does?
Solution: In the solid, the ions are held in fixed positions in the lattice and cannot move. When molten, the lattice breaks down and the ions are free to move to the electrodes, carrying charge.

4.2Hydrogen–oxygen fuel cells

A fuel cell uses hydrogen and oxygen to produce electricity, with water as the only product:

2H2 + O2 → 2H2O
Advantages over petrol enginesDisadvantages
Only product is water — no CO2 or pollutants at point of useHydrogen is difficult and expensive to store and transport (highly flammable, needs high pressure)
More efficient energy conversionProducing the hydrogen often uses fossil fuels
Quiet, few moving partsExpensive catalysts; limited refuelling infrastructure
Topic 5 · 1 unit

Chemical energetics

5.1Exothermic and endothermic reactions

ExothermicEndothermic
EnergyReleased to the surroundingsTaken in from the surroundings
Temperature of surroundingsIncreasesDecreases
ΔHNegativePositive
Energy level diagramProducts below reactantsProducts above reactants
ExamplesCombustion, neutralisation, most displacement reactions, respirationThermal decomposition, photosynthesis, dissolving some salts
Energy reactants products Ea ΔH −ve Exothermic Energy reactants products Ea ΔH +ve Endothermic
The hump is the activation energy — the minimum energy colliding particles need to react.
Bond energy reasoningBreaking bonds is always endothermic (energy in); making bonds is always exothermic (energy out).
If more energy is released making bonds than was used breaking them, the reaction is exothermic overall.
Skill check: A student dissolves a salt in water and the temperature falls from 21 °C to 15 °C. Classify the process and state the sign of ΔH.
Solution: The surroundings lost energy to the process, so it is endothermic and ΔH is positive.
Topic 6 · 4 units

Chemical reactions

6.1Physical and chemical changes  6.2Rate of reaction

Physical change: no new substance formed, usually easily reversible (melting, dissolving). Chemical change: a new substance is formed, usually hard to reverse, often with an energy change, colour change, gas or precipitate.

Collision theory — the explanation for every rate factorReactions happen when particles collide with enough energy (the activation energy) and in the correct orientation. Anything that increases the frequency of successful collisions increases the rate.
Factor increasedEffect on rateExplanation
Concentration (or pressure for gases)FasterMore particles in the same volume → more frequent collisions
TemperatureFasterParticles have more kinetic energy → collide more often and a greater proportion have energy ≥ activation energy
Surface area (smaller pieces)FasterMore particles exposed at the surface → more frequent collisions
Catalyst addedFasterProvides an alternative route with a lower activation energy; it is not used up
Explaining a temperature increase only as "particles move faster". The bigger effect is that a greater proportion of collisions have energy above the activation energy — you need both halves for full marks.
Rate experiments are common in P3/P4: measure gas volume against time with a gas syringe, measure mass loss on a balance, or time how long a cross takes to disappear (sodium thiosulfate + acid). On a graph of product against time, the steepest gradient is the fastest rate, and the curve flattens when a reactant is used up.
Skill check: Powdered calcium carbonate reacts faster with acid than the same mass of large lumps. Explain why, and state whether the total volume of gas differs.
Solution: The powder has a much larger surface area, so more carbonate particles are exposed to acid particles and collisions are more frequent — a faster rate. The total volume of gas is the same, because the amount (moles) of calcium carbonate is unchanged; only the speed differs.

6.3Reversible reactions and equilibrium

A reversible reaction (⇌) can go both ways. In a closed system it reaches equilibrium: the forward and backward reactions occur at the same rate, so the concentrations of reactants and products stay constant (they are not equal — just unchanging).

The classic reversible reaction is the hydration of anhydrous copper(II) sulfate — white ⇌ blue, used as the test for water.

Shifting an equilibrium
  • Increase concentration of a reactant → shifts right (more product).
  • Increase pressure → shifts to the side with fewer gas molecules.
  • Increase temperature → shifts in the endothermic direction.
  • A catalyst does not shift the position of equilibrium — it only makes it reached faster.

The Haber process (ammonia): N2 + 3H2 ⇌ 2NH3 — about 450 °C, 200 atm, iron catalyst. The temperature is a compromise: the forward reaction is exothermic so a lower temperature would give more ammonia, but the rate would be uneconomically slow.

Skill check: In the Haber process, why is a high pressure used?
Solution: There are 4 molecules of gas on the left (1 N2 + 3 H2) and only 2 on the right. High pressure shifts the equilibrium towards the side with fewer gas molecules — the ammonia side — increasing the yield (and it also increases the rate).

6.4Redox

Definitions — know both setsIn terms of oxygen: oxidation is gain of oxygen; reduction is loss of oxygen.
In terms of electrons: OIL RIG — Oxidation Is Loss of electrons, Reduction Is Gain of electrons.
An oxidising agent oxidises another substance and is itself reduced (it gains electrons). A reducing agent reduces another substance and is itself oxidised.

Oxidation numbers can also be used: oxidation is an increase in oxidation number, reduction a decrease. Roman numerals in names give the oxidation number, e.g. iron(III) is Fe3+.

TestObservation
Test for an oxidising agent — add aqueous potassium iodideSolution turns brown (iodine is displaced)
Test for a reducing agent — add acidified potassium manganate(VII)Turns from purple to colourless
Worked example

In Zn + CuSO4 → ZnSO4 + Cu, identify what is oxidised and what is reduced.

  1. Zn → Zn2+ + 2e: zinc loses electrons, so zinc is oxidised (and is the reducing agent).
  2. Cu2+ + 2e → Cu: copper ions gain electrons, so Cu2+ is reduced (and is the oxidising agent).
Skill check: In the extraction of iron, Fe2O3 + 3CO → 2Fe + 3CO2. Which species is reduced and which is the reducing agent?
Solution: Fe2O3 loses oxygen, so iron(III) oxide is reduced. Carbon monoxide gains oxygen — it is oxidised, which makes CO the reducing agent.
Topic 7 · 3 units

Acids, bases and salts

7.1Characteristic properties of acids and bases

DefinitionsAn acid is a substance that produces H+ ions in aqueous solution (a proton donor). A base is a substance that reacts with an acid to form a salt and water (a proton acceptor); an alkali is a soluble base, producing OH ions in solution.
Reaction of a dilute acid with…ProductsObservation
A reactive metalsalt + hydrogenEffervescence; gas 'pops' with a lighted splint
A base or alkali (neutralisation)salt + waterTemperature rises (exothermic)
A carbonatesalt + water + carbon dioxideEffervescence; gas turns limewater milky
H+(aq) + OH(aq) → H2O(l)  — the ionic equation for every neutralisation

Strong vs weak: a strong acid is fully dissociated into ions in solution (HCl, HNO3, H2SO4); a weak acid is only partially dissociated (ethanoic acid, carbonic acid). This is different from concentration — a concentrated weak acid is still weak.

pH0–34–678–1112–14
NatureStrongly acidicWeakly acidicNeutralWeakly alkalineStrongly alkaline
Universal indicatorRedOrange/yellowGreenBluePurple

Indicators: litmus is red in acid, blue in alkali. Methyl orange is red in acid, yellow in alkali. Thymolphthalein is colourless in acid, blue in alkali.

Confusing strong/weak (degree of dissociation) with concentrated/dilute (amount of solute per volume). Both words appear in the same question specifically to test this.

7.2Oxides

Type of oxideNatureExamples
Acidic — non-metal oxidesReact with bases/alkalis to form saltsCO2, SO2, NO2
Basic — metal oxidesReact with acids to form saltsCuO, MgO, CaO
AmphotericReact with both acids and basesAl2O3, ZnO
NeutralReact with neitherH2O, CO, NO

7.3Preparation of salts

Which method? Decide from solubility
  1. Soluble salt from an insoluble base/carbonate — add the solid to warm dilute acid in excess, stir until no more dissolves, filter off the unreacted excess, then crystallise the filtrate (evaporate to the point of crystallisation, cool, filter and dry between filter papers).
  2. Soluble salt from an alkali (both solutions) — use a titration, because there is no solid excess to filter off. Find the exact volume needed with an indicator, then repeat without the indicator and crystallise.
  3. Insoluble saltprecipitation: mix two solutions containing the required ions, then filter, wash the residue with distilled water and dry.
Solubility rules to memoriseAlways soluble: all sodium, potassium and ammonium salts; all nitrates.
Chlorides soluble except silver and lead.
Sulfates soluble except barium, calcium and lead.
Carbonates insoluble except sodium, potassium and ammonium.
Worked example

Describe how to prepare pure, dry crystals of copper(II) sulfate from copper(II) oxide.

  1. Warm dilute sulfuric acid in a beaker.
  2. Add copper(II) oxide a little at a time, stirring, until no more dissolves (excess present) — the solution turns blue.
  3. Filter to remove the unreacted copper(II) oxide.
  4. Heat the blue filtrate to evaporate about half the water, until a saturated solution forms (crystallisation point).
  5. Leave to cool and crystallise, then filter off the crystals and dry them between sheets of filter paper.
Skill check: Why can barium sulfate not be made by adding an excess solid to acid, and what method is used instead?
Solution: Barium sulfate is insoluble, so it would form a coating on the solid and the reaction would stop; it also could not be separated from unreacted excess. Instead use precipitation: mix solutions of a soluble barium salt (e.g. barium nitrate) and a soluble sulfate (e.g. sodium sulfate), then filter, wash and dry the precipitate.
Topic 8 · 5 units

The Periodic Table

8.1Arrangement of elements

Elements are arranged in order of increasing proton number. Groups (columns) contain elements with the same number of outer-shell electrons and hence similar chemical properties; periods (rows) show the number of occupied shells. Metals are on the left, non-metals on the right.

Across a period, elements change from metallic to non-metallic. Down a group, atoms gain more shells, so the atomic radius increases and the outer electrons are further from the nucleus and more shielded.

8.2Group I — the alkali metals  8.3Group VII — the halogens

Group I (Li, Na, K)Group VII (Cl, Br, I)
Physical trend down the groupDensity increases; melting point decreases; all soft, low-density metalsColour gets darker; melting/boiling points increase (Cl2 gas → Br2 liquid → I2 solid)
Reactivity down the groupIncreasesDecreases
WhyOuter electron is further from the nucleus and more shielded, so it is lost more easilyOuter shell is further from the nucleus and more shielded, so an electron is gained less easily
Typical reactionWith water → metal hydroxide + hydrogen; the alkali formed turns litmus blueDisplacement: a more reactive halogen displaces a less reactive one from its salt solution

Group I with water: lithium fizzes steadily; sodium melts into a ball and moves rapidly on the surface; potassium reacts violently and the hydrogen produced ignites with a lilac flame.

Worked example — displacement

Predict what happens when chlorine solution is added to potassium bromide solution, and write the equation.

  1. Chlorine is above bromine in Group VII, so it is more reactive and displaces bromide.
  2. Observation: the solution turns orange/brown as bromine is formed.
  3. Cl2 + 2KBr → 2KCl + Br2
Skill check: Explain, in terms of electrons, why potassium is more reactive than sodium.
Solution: Potassium's outer electron is in a shell further from the nucleus and is shielded by more inner shells, so the attraction from the nucleus is weaker. The outer electron is therefore lost more easily, and losing that electron is what Group I reactions require.

8.4Transition elements  8.5Noble gases

Transition elements (the central block) differ from Group I metals: they have high densities, high melting points, form coloured compounds, show variable oxidation states, and are often used as catalysts (iron in the Haber process, nickel in hydrogenation). They are also much harder and less reactive than Group I metals.

Noble gases (Group VIII/0) are unreactive because they already have a full outer electron shell, so they have no tendency to gain, lose or share electrons. Uses follow from that inertness: helium in balloons (low density, non-flammable), argon in lamps and as an inert welding atmosphere.

Skill check: Give three ways copper differs from potassium as a metal.
Solution: Any three of: copper has a much higher density; a much higher melting point; is far less reactive (does not react with water); forms coloured compounds (blue Cu²⁺) rather than white ones; shows variable oxidation states; and can act as a catalyst.
Topic 9 · 6 units

Metals

9.1Properties  9.2Uses  9.3Alloys

General properties of metals: good conductors of heat and electricity, malleable, ductile, shiny when freshly cut, generally high melting points and densities — all explained by metallic bonding (2.7).

Uses linked to properties: copper for electrical wiring (excellent conductor, ductile); aluminium for aircraft and overhead cables (low density, corrosion-resistant due to its oxide layer); mild steel for car bodies and construction (strong, cheap); stainless steel for cutlery and chemical plant (resists corrosion).

AlloysAn alloy is a mixture of a metal with other elements. Alloys are harder and stronger than the pure metal because the different-sized atoms disrupt the regular layers, making it harder for them to slide over each other.
AlloyMade fromProperty/use
BrassCopper + zincHarder than copper; musical instruments, fittings
Mild steelIron + small % carbonStrong, malleable; car bodies, girders
Stainless steelIron + chromium + nickelResists corrosion; cutlery, sinks

9.4Reactivity series  9.5Corrosion

K > Na > Ca > Mg > Al > (C) > Zn > Fe > (H) > Cu > Ag > Au
MetalWith cold waterWith dilute acid
K, Na, CaReact readily → hydroxide + hydrogenViolently (dangerous)
Mg, Zn, FeLittle or no reaction (Mg reacts with steam)React → salt + hydrogen
Cu, Ag, AuNo reactionNo reaction (below hydrogen)

Displacement: a more reactive metal displaces a less reactive one from its compound (e.g. zinc displaces copper from copper(II) sulfate — the blue solution fades and a brown/pink solid forms). These reactions are exothermic and are used to place unknown metals in the series.

RustingIron rusts when in contact with both oxygen (air) and water — both are needed. Salt speeds it up.

Preventing rust: barrier methods (painting, greasing, plastic coating, galvanising with zinc) keep out air and water. Sacrificial protection works differently: a more reactive metal such as zinc or magnesium is attached and corrodes instead of the iron, because it loses electrons more readily. Galvanising does both.

A classic P3/P4 experiment: iron nails in four test tubes — (1) water and air, (2) boiled water with oil on top (no air), (3) anhydrous calcium chloride with dry air (no water), (4) salt water. Only tubes 1 and 4 rust, proving both oxygen and water are needed and that salt accelerates it.
Skill check: A ship's steel hull has blocks of magnesium bolted to it. Explain how this prevents rusting.
Solution: Magnesium is more reactive than iron, so it loses electrons more readily and corrodes in preference to the iron — sacrificial protection. The blocks are gradually eaten away and must be replaced, but the hull is protected even if its paint is scratched.

9.6Extraction of metals

Method of extraction depends on reactivity
  • More reactive than carbon (K, Na, Ca, Mg, Al) → electrolysis of the molten compound (carbon cannot reduce them).
  • Less reactive than carbon (Zn, Fe, Cu) → reduction with carbon (cheaper).
  • Very unreactive (Ag, Au) → found native as the element.

Iron in the blast furnace — raw materials: iron ore (haematite, Fe2O3), coke, limestone and hot air.

  1. Coke burns: C + O2 → CO2 (exothermic — provides the heat)
  2. Carbon dioxide is reduced: CO2 + C → 2CO
  3. Carbon monoxide reduces the ore: Fe2O3 + 3CO → 2Fe + 3CO2
  4. Limestone removes the sand impurity: CaCO3 → CaO + CO2, then CaO + SiO2 → CaSiO3 (slag, which floats on the molten iron and is tapped off separately)

Aluminium by electrolysis: aluminium oxide is dissolved in molten cryolite to lower the melting point and so reduce energy costs. At the carbon cathode Al3+ + 3e → Al; at the carbon anode 2O2− → O2 + 4e. The anodes burn away in the oxygen produced and must be replaced regularly.

Skill check: Why is aluminium extracted by electrolysis rather than by heating with carbon, even though electrolysis is far more expensive?
Solution: Aluminium is more reactive than carbon, so carbon cannot reduce aluminium oxide — the aluminium holds its oxygen too strongly. Electrolysis is the only viable method despite the high electrical energy cost.
Topic 10 · 3 units

Chemistry of the environment

10.1Water  10.2Fertilisers

Water treatment for drinking: sedimentation/filtration to remove solids, then chlorination to kill bacteria. Note this makes water safe, not chemically pure.

Tests: for water — anhydrous copper(II) sulfate white → blue, or cobalt(II) chloride blue → pink. For pure water — boiling point exactly 100 °C and freezing point exactly 0 °C at standard atmospheric pressure.

Fertilisers supply the elements plants need: nitrogen, phosphorus and potassium (NPK). Nitrogen promotes leaf/stem growth (proteins), phosphorus root growth, potassium flowering and disease resistance. Ammonium salts and nitrates are common nitrogenous fertilisers.

EutrophicationExcess fertiliser is washed into rivers and lakes → algae grow rapidly (algal bloom) → algae block light and later die → bacteria decompose them, using up dissolved oxygen → fish and other aquatic life die.

10.3Air quality and climate

Clean dry air is approximately 78% nitrogen, 21% oxygen, with argon, carbon dioxide and other gases making up the rest.

PollutantSourceHarmful effect
Carbon monoxide, COIncomplete combustion of fuelsToxic — binds to haemoglobin, reducing oxygen transport
Sulfur dioxide, SO2Combustion of fuels containing sulfur impuritiesCauses acid rain — damages buildings, trees and aquatic life
Oxides of nitrogen, NOxFormed in car engines at high temperature (N2 + O2)Acid rain and photochemical smog; respiratory problems
ParticulatesIncomplete combustion (soot)Respiratory problems; reduced visibility

Catalytic converters in cars reduce these pollutants, e.g. 2CO + 2NO → 2CO2 + N2, converting toxic gases into harmless ones.

The greenhouse effectGreenhouse gases — mainly carbon dioxide, methane and water vapour — absorb infrared radiation re-emitted from the Earth's surface and re-radiate it back, warming the atmosphere. Increasing concentrations (from burning fossil fuels, deforestation and agriculture) enhance this effect, causing climate change: rising average temperatures, melting ice, rising sea levels and more extreme weather.
Skill check: Explain how burning a fuel containing sulfur leads to damage to a limestone building.
Solution: Burning produces sulfur dioxide, which dissolves in rainwater to form an acidic solution — acid rain. Limestone is calcium carbonate, which reacts with acids (carbonate + acid → salt + water + carbon dioxide), so the stone is gradually eroded away.
Topic 11 · 8 units

Organic chemistry

Organic chemistry looks like a lot of memorising, but it collapses into four families and a handful of reactions. Learn the general formulae, the functional groups, and the reagent-plus-conditions for each reaction, and most questions become predictable.

11.1Formulae and terminology  11.2Naming organic compounds

Key termsA homologous series is a family of compounds with the same general formula and functional group, showing a gradual change in physical properties and similar chemical properties, with each member differing by CH2.
A functional group is the atom or group of atoms responsible for a compound's characteristic reactions.
Isomers have the same molecular formula but different structural formulae.
Saturated = only single carbon–carbon bonds; unsaturated = contains a C=C double bond.
SeriesGeneral formulaFunctional groupName endingFirst members
AlkanesCnH2n+2C–C single bonds-aneMethane CH4, ethane C2H6, propane C3H8, butane C4H10
AlkenesCnH2nC=C-eneEthene C2H4, propene C3H6
AlcoholsCnH2n+1OH–OH-olMethanol CH3OH, ethanol C2H5OH
Carboxylic acidsCnH2n+1COOH–COOH-oic acidMethanoic acid HCOOH, ethanoic acid CH3COOH

Naming: the stem gives the number of carbon atoms — meth- (1), eth- (2), prop- (3), but- (4) — and the ending gives the family.

Know the difference between the three formulae: molecular (C2H6O), structural (CH3CH2OH) and displayed (every atom and every bond drawn out). If a question says "draw the displayed formula", you must show all the bonds, including every C–H.

11.3Fuels

Fossil fuels are coal, natural gas and petroleum. Petroleum is a mixture of hydrocarbons separated by fractional distillation, which works because different fractions have different boiling points — the column is hottest at the bottom, so smaller molecules with lower boiling points rise higher before condensing.

Fraction (top → bottom)Use
Refinery gasBottled gas for heating and cooking
Gasoline/petrolFuel for cars
NaphthaFeedstock for making chemicals
Kerosene/paraffinJet fuel
Diesel oilFuel for diesel engines
Fuel oilFuel for ships and power stations
Lubricating fraction / bitumenLubricants, waxes, polishes; road surfacing

Combustion: complete combustion (plenty of oxygen) gives carbon dioxide and water; incomplete combustion (limited oxygen) gives carbon monoxide (toxic) and/or carbon (soot). Methane is the main constituent of natural gas: CH4 + 2O2 → CO2 + 2H2O

11.4Alkanes  11.5Alkenes

Alkanes are saturated hydrocarbons with only single covalent bonds. They are generally unreactive, except for combustion and substitution with chlorine.

SubstitutionIn a substitution reaction, one atom or group of atoms is replaced by another. Alkanes react with chlorine in a photochemical reaction, with ultraviolet light providing the activation energy (monosubstitution only at this level):
CH4 + Cl2 → CH3Cl + HCl

Alkenes contain a C=C double bond and are unsaturated, which makes them much more reactive than alkanes.

CrackingCracking breaks larger alkane molecules into smaller, more useful ones using a high temperature and a catalyst, producing alkenes and hydrogen.
Why do it: there is greater demand for short-chain hydrocarbons (petrol) than the long-chain fractions supply, and cracking also produces the alkenes needed to make polymers.
Example: C10H22 → C8H18 + C2H4
The test for unsaturationAdd aqueous bromine. An alkene decolourises it — orange/yellow-brown to colourless. An alkane leaves it unchanged.

Addition reactions of alkenes — the double bond opens and only one product is formed:

ReagentConditionsProduct from ethene
Bromine (or aqueous bromine)Room temperature1,2-dibromoethane, CH2BrCH2Br
HydrogenNickel catalystEthane, CH3CH3
SteamAcid catalystEthanol, CH3CH2OH
Skill check: Two colourless liquids are hexane and hexene. Describe a test to tell them apart, with results.
Solution: Add aqueous bromine to each and shake. The hexene (unsaturated, C=C) decolourises the bromine — orange to colourless — by an addition reaction. The hexane (saturated) leaves it orange/unchanged.

11.6Alcohols  11.7Carboxylic acids

FermentationCatalytic addition of steam to ethene
Raw materialAqueous glucose (from plants — renewable)Ethene (from petroleum — non-renewable)
Conditions25–35 °C, yeast, absence of oxygen300 °C, 6000 kPa (60 atm), acid catalyst
Rate / processSlow, batch processFast, continuous process
PurityImpure — needs fractional distillationPure product

Uses of ethanol: as a solvent and as a fuel. Alcohols burn in oxygen to give carbon dioxide and water: C2H5OH + 3O2 → 2CO2 + 3H2O

Carboxylic acids behave like other acids — they are weak acids, so they react in the usual three ways:

Reacts withProductsExample with ethanoic acid
A metalsalt + hydrogenSodium ethanoate + H2
A basesalt + waterSodium ethanoate + H2O
A carbonatesalt + water + carbon dioxideSodium ethanoate + H2O + CO2

Making ethanoic acid by oxidising ethanol: (a) with acidified aqueous potassium manganate(VII) (purple → colourless), or (b) by bacterial oxidation, which is how vinegar is produced and why wine turns sour in air.

EstersA carboxylic acid reacts with an alcohol, using an acid catalyst, to form an ester and water. Esters are sweet-smelling and used in perfumes and flavourings.
Example: ethanoic acid + ethanol → ethyl ethanoate + water.
Ester names take the alcohol part first (as -yl) and the acid part second (as -oate): ethanol + propanoic acid → ethyl propanoate. Getting the order backwards is a very common slip.
Skill check: Name the ester made from methanol and ethanoic acid, and state the catalyst.
Solution: The alcohol (methanol) gives "methyl" and the acid (ethanoic) gives "ethanoate", so the ester is methyl ethanoate. The catalyst is an acid (concentrated sulfuric acid).

11.8Polymers

DefinitionPolymers are large molecules built up from many smaller molecules called monomers. Plastics are made from polymers.
Addition polymerisationCondensation polymerisation
MonomersAlkenes (contain C=C)Two different monomers, each with two functional groups
Other productNone — the polymer is the only productA small molecule is lost each time (usually water)
ExamplesPoly(ethene) from ethene; poly(propene) from propenePolyamides (dicarboxylic acid + diamine, amide linkage); polyesters (dicarboxylic acid + diol, ester linkage)
Method — drawing an addition polymer1. Draw the monomer with its C=C. 2. Change the double bond to a single bond. 3. Draw a bond extending from each end (the "continuation bonds"). 4. Enclose in brackets with n outside. Reverse the steps to go from repeat unit back to monomer.
Worked example

Ethene, CH2=CH2, polymerises to poly(ethene). Give the repeat unit.

  1. Break the double bond to a single bond between the two carbons.
  2. Add a continuation bond at each end.
  3. Repeat unit: –[CH2–CH2]–n

Disposal problems: most addition polymers are non-biodegradable, so they persist in landfill for centuries; burning them can release toxic gases (such as HCl from PVC) and carbon dioxide; and litter harms wildlife. Recycling reduces this but requires sorting by polymer type.

Skill check: State two differences between addition and condensation polymerisation.
Solution: (1) Addition uses monomers containing a C=C double bond (alkenes), whereas condensation uses monomers with two functional groups each. (2) In addition polymerisation the polymer is the only product, whereas condensation also produces a small molecule such as water each time a link forms.
Topic 12 · 5 units

Experimental techniques and chemical analysis

12.1Experimental design  12.2Acid–base titrations

Apparatus for measuring volume: a burette (accurate, variable volumes, readings to 0.05 cm³), a pipette (one fixed accurate volume), a measuring cylinder (approximate volumes only). Choose the burette or pipette whenever accuracy matters.

Titration method — the standard sequence
  1. Use a pipette to transfer a measured volume of one solution (e.g. 25.0 cm³ of alkali) into a conical flask.
  2. Add a few drops of a suitable indicator.
  3. Fill a burette with the acid and record the initial reading.
  4. Add acid, swirling constantly, until the indicator just changes colour permanently — the end point. Add dropwise near the end.
  5. Record the final reading; titre = final − initial.
  6. Repeat until concordant titres (within 0.10 cm³) are obtained, then average only the concordant ones.
Averaging all the titres including the rough one. Only concordant results are averaged — the first, rough titration is used to find the approximate end point and is then discarded. Also: universal indicator is not suitable for titrations, because it changes gradually through many colours rather than sharply.

12.3Chromatography  12.4Separation and purification

Paper chromatography separates mixtures of soluble coloured (or, with a locating agent, colourless) substances. The baseline is drawn in pencil — ink would dissolve and run — and the solvent level must start below the baseline, or the spots wash off into the solvent.

Rf = distance moved by the substance ÷ distance moved by the solvent front

Rf values are always between 0 and 1, and are constant for a given substance and solvent, so they identify substances by comparison. A pure substance gives one spot; a mixture gives more than one.

TechniqueSeparatesPrinciple
FiltrationInsoluble solid from a liquidSolid is trapped as the residue; liquid passes through as the filtrate
CrystallisationDissolved solid from its solutionEvaporate to saturation, cool; the solid is less soluble when cold and crystallises
Simple distillationSolvent from a solution (keeping the solvent)Liquid evaporates, then condenses in the condenser
Fractional distillationMiscible liquids (e.g. ethanol from water)Different boiling points; the fractionating column lets the lower-boiling liquid pass first
In a distillation diagram, check three things: the thermometer bulb is level with the side-arm, the condenser has water entering at the lower end (so it fills and flows counter to the vapour), and the apparatus is not sealed — a closed system would explode as pressure builds.

Assessing purity: a pure substance has a sharp, fixed melting and boiling point. Impurities lower the melting point and raise the boiling point, and make the melting occur over a range rather than at one temperature.

Skill check: A chromatogram shows a spot 4.5 cm from the baseline; the solvent front travelled 9.0 cm. Find the Rf value.
Solution: Rf = 4.5 ÷ 9.0 = 0.50 (no units — it is a ratio, and always less than 1).

12.5Identification of ions and gases

All the required tests are collected in the qualitative analysis tables at the top of this guide — gases, cations, anions and flame tests. Remember: those tables are given to you in Papers 3 and 4 but not in Paper 2.

How to write a test answer that scores full marksState the reagent, the procedure, and the observation — all three. "Add aqueous sodium hydroxide and warm; damp red litmus paper held over the tube turns blue, showing ammonia and therefore the ammonium ion" scores; "test with NaOH" does not.
Worked example — deducing an unknown

A colourless solution gives a white precipitate with aqueous sodium hydroxide which dissolves in excess, and a white precipitate with acidified barium nitrate. Identify the salt.

  1. White ppt. soluble in excess NaOH → Al3+ or Zn2+ (Ca2+ is ruled out — its precipitate is insoluble in excess).
  2. White ppt. with acidified barium nitrate → sulfate, SO42−.
  3. So the salt is aluminium sulfate or zinc sulfate — to distinguish, add aqueous ammonia: with Al3+ the precipitate is insoluble in excess; with Zn2+ it dissolves.
Worth 20% of your grade

Practical skills — Paper 3 and Paper 4

Everyone sits one practical paper, and it is pure AO3. Papers 3 and 4 test identical skills — the only difference is whether you handle the apparatus yourself.

The experimental contexts you must know

  • Quantitative measurement of volumes, masses, temperatures, times and lengths
  • Rates of reaction; temperature changes during reactions; heating and cooling curves
  • Salt preparation; solubility; melting and boiling points
  • Separation and purification: filtration, crystallisation, simple and fractional distillation, chromatography
  • Electrolysis; displacement reactions of metals and halogens; conditions for rusting
  • Identification of metal ions, non-metal ions and gases; chemical tests for water
  • Test-tube reactions of dilute acids, including ethanoic acid; tests for oxidising and reducing agents
  • Titrations, and unfamiliar procedures with simple apparatus

Recording observations — what examiners want to see

Describing an observationNever write just "a reaction happened". Name what you actually see:
  • Colour — and be precise: "red-brown precipitate", not "brown stuff".
  • Precipitate — say whether it forms, its colour, and whether it dissolves in excess.
  • Gas — "effervescence/bubbles" plus the identifying test result.
  • Temperature — "the test tube became warm" indicates an exothermic reaction.
  • Solid disappearing — "the solid dissolved" or "the magnesium disappeared".
  • If nothing happens, write "no visible change" — a blank space scores zero, but that phrase can score.
Tables and readings
  • Column headings carry the quantity and unit separated by a solidus: time / s, volume / cm³. Units never appear beside the numbers in the body.
  • Burette readings are recorded to 2 decimal places, ending in .00 or .05.
  • All raw readings in a column have the same number of decimal places.
  • Read the bottom of the meniscus at eye level to avoid parallax error.
  • Calculated values should carry the same number of significant figures as the least precise raw data used.

Graphs and evaluation

  • Independent variable on the x-axis; label both axes with quantity and unit.
  • Scales must let the points fill more than half the grid in both directions, using sensible ratios.
  • Plot as small crosses (×) or encircled dots, accurate to half a small square.
  • Draw a single thin best-fit line or smooth curve; ignore clearly anomalous points when drawing it (but circle and mention them).
  • For a gradient, use a triangle whose hypotenuse spans at least half the line, and mark it on the graph.
Source of errorEffectImprovement to suggest
Heat loss to the surroundingsTemperature rise measured is too smallInsulate the container and use a lid
Gas escaping before the bung is fittedVolume of gas collected is too lowFit the bung immediately; use a syringe attached before mixing
Reading a burette or cylinder at an angleSystematic volume errorRead the bottom of the meniscus at eye level
Solution splashing out of the flaskLoss of reactant, so the titre is wrongSwirl gently; rinse the flask walls with distilled water
Judging a colour change by eyeRandom error in the end pointAdd dropwise near the end; use a white tile behind the flask
ConclusionsQuote the actual data and then judge: "The temperature rise was greatest with the powdered solid (12 °C compared with 7 °C for lumps), so the results support the prediction that a larger surface area increases the rate." Naming the comparison is what earns the mark.

Safety should match the hazard: acids and alkalis → wear eye protection; heating → use tongs and a heatproof mat, point the test tube away from people; toxic or irritant gases (chlorine, sulfur dioxide) → work in a fume cupboard; flammable liquids (ethanol) → keep away from naked flames and heat with a water bath.

Reference

Free past papers & how to revise chemistry

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The method that fits how chemistry is marked

  1. Learn the tests table cold. It is provided in the practical paper but not in Paper 2, and it appears in almost every theory paper — the cheapest marks in the subject.
  2. Drill moles. One mole question a day for a month covers nearly every calculation the exam can ask.
  3. Practise explanations out loud. Most explanation marks follow a fixed pattern: particles → forces → what happens to them. Say it until it is automatic.
  4. Write equations from words. Take word equations from past papers and convert them to balanced symbol equations with state symbols.
  5. Do the practical papers. 20% of your grade, and the question patterns repeat heavily year to year.

Edvia Free Resources — O Level Chemistry 5070. Original notes and worked examples written for the Cambridge O Level Chemistry 5070 syllabus for examination in 2026, 2027 and 2028. The qualitative analysis tables reproduce the standard test results as listed in the syllabus for candidate use. An independent free study resource, not affiliated with or endorsed by Cambridge University Press & Assessment. Share it freely — it will always be free.

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