Free O Level Additional Mathematics 4037 Handouts — Edvia College
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Additional Mathematics 4037 — chapter handouts

One handout per topic, in plain English. Read the handout before the textbook, not after it — each one takes about five minutes and is designed to make the idea land first, so the formal version has somewhere to stick.

14 handoutsCambridge O LevelPrintableFree to copy and share
Open the full 4037 study guide → Practice these → All subjects

Topics

  1. Functions
  2. Quadratic functions
  3. Factors of polynomials
  4. Equations, inequalities and graphs
  5. Simultaneous equations
  6. Logarithmic and exponential functions
  7. Straight-line graphs
  8. Coordinate geometry of the circle
  9. Circular measure
  10. Trigonometry
  11. Permutations and combinations
  12. Series
  13. Vectors in two dimensions
  14. Calculus
Topic 1

Functions

A function is a machine: put a number in, get exactly one number out — and the whole topic is about controlling that machine.

Picture itA vending machine takes a code and gives you one item. Press B4 and you always get the same thing. If pressing B4 sometimes gave crisps and sometimes chocolate, it would be broken — and that is precisely why a function must give one output per input.

Domain and range are the input and output sets

The domain is every value you are allowed to put in; the range is every value that can come out. For f(x) = √x the domain is x ≥ 0, because you cannot square-root a negative, and the range is f(x) ≥ 0.

Composite functions run one machine into another

fg(x) means do g first, then f. The order matters and is the commonest slip in the topic — fg(x) and gf(x) are usually different. Work from the inside out.

Inverse functions undo

f⁻¹ reverses f. Find it by writing y = f(x), swapping x and y, then rearranging for y. A function only has an inverse if it is one-to-one — each output comes from just one input — which is why the domain is sometimes restricted.

Modulus makes everything positive

|x| is the size of x ignoring its sign. Graphs of |f(x)| reflect any part below the x-axis up above it. Solving |x − 3| = 5 means considering both x − 3 = 5 and x − 3 = −5, giving two answers.

The bit that catches people outThe graph of f⁻¹ is the reflection of f in the line y = x, not in the x-axis or y-axis. That reflection is why swapping x and y is the algebraic method — the two are the same operation.

The grown-up words

What it meansWhat it is calledNote
Set of allowed inputsdomainWatch for square roots and division by zero
Set of possible outputsrange
One function inside anothercomposite functionfg means g first
The function that undoes finverse functionf⁻¹, reflect in y = x
Each output from only one inputone-to-oneRequired for an inverse to exist
Size ignoring signmodulus|x| — gives two cases when solving

Check you have got it

If f(x) = 2x + 1 and g(x) = x², find fg(3).
g first: g(3) = 9. Then f(9) = 19.
Why does f(x) = x² have no inverse over all real numbers?
It is not one-to-one — both 3 and −3 give 9, so the inverse would not know which to return. Restricting the domain to x ≥ 0 fixes it.
Edvia Free Resources · Additional Mathematics 4037 · Topic 1 — free to copy and share
Topic 2

Quadratic functions

Every quadratic is the same U-shaped curve, moved and stretched — and completing the square tells you exactly where it has been moved to.

Picture itThrow a ball and its path is a quadratic. Ask where it peaks and you are asking for the vertex. Complete the square and the peak's coordinates fall out of the algebra without any calculus at all.

Completing the square reveals the vertex

Rewriting ax² + bx + c as a(x + p)² + q tells you immediately that the vertex is at (−p, q). It also gives you the maximum or minimum value for free — q — and whether it is a maximum or minimum depends on the sign of a.

The discriminant counts the roots

b² − 4ac. If it is positive, two distinct real roots. If zero, one repeated root — which geometrically means the curve just touches the axis, so it is also the condition for a tangent. If negative, no real roots and the curve misses the axis entirely.

Three ways to solve, and when to use each

Factorise when the numbers are friendly. Complete the square when you want the vertex or an exact surd answer. Use the formula when nothing factorises. All three give the same roots.

Quadratic inequalities need the sketch

Find the roots, sketch the parabola, then read off where it is above or below the axis. For x² − 5x + 6 > 0 the curve is above the axis outside the roots, so x < 2 or x > 3. Trying to do this algebraically without the sketch is how people get the inequality backwards.

The bit that catches people out'Discriminant = 0' is the condition for a tangent, and questions rarely say the word 'discriminant' — they say 'the line is a tangent to the curve' and expect you to set the two equal, form a quadratic, and set b² − 4ac to zero.

The grown-up words

What it meansWhat it is calledNote
a(x + p)² + q formcompleted squareVertex at (−p, q)
b² − 4acdiscriminantCounts the real roots
Turning point of the parabolavertexMaximum if a < 0, minimum if a > 0
Touches but does not crosstangentDiscriminant = 0
Where the curve meets the x-axisrootsSolutions of the equation

Check you have got it

For what value of k is y = kx − 2 a tangent to y = x² − 3x + 2?
Set equal: x² − (3+k)x + 4 = 0. Tangent means discriminant zero: (3+k)² − 16 = 0, so k = 1 or k = −7.
Express x² + 6x + 11 in completed square form and state the minimum value.
(x + 3)² + 2. The minimum is 2, at x = −3.
Edvia Free Resources · Additional Mathematics 4037 · Topic 2 — free to copy and share
Topic 3

Factors of polynomials

If substituting a number into a polynomial gives zero, you have found a factor — and that turns a hard cubic into an easy quadratic.

Picture itA cubic looks intimidating until you spot that x = 1 makes it vanish. Then (x − 1) divides out cleanly and you are left with a quadratic you can solve on sight. One lucky guess collapses the whole problem.

The factor theorem

If f(a) = 0 then (x − a) is a factor. To find that first root, try the factors of the constant term — for x³ − 6x² + 11x − 6, try ±1, ±2, ±3, ±6. One of them almost always works in an exam.

The remainder theorem

f(a) gives the remainder when f(x) is divided by (x − a). So the factor theorem is just the special case where the remainder happens to be zero. Questions about 'the remainder is 5' are asking you to set f(a) = 5.

Then divide and finish

Once you have one factor, use long division or comparing coefficients to get the quadratic, then factorise or use the formula. Three roots for a cubic, if they are all real.

Watch for (ax − b) factors

If the leading coefficient is not 1, the root may be a fraction. For 2x³ + …, try x = ½ as well as whole numbers — and the corresponding factor is (2x − 1), not (x − ½).

The bit that catches people outThe factor theorem uses (x − a) with a minus sign. If (x + 2) is a factor, the root is x = −2, so you substitute −2, not 2. Getting this sign wrong makes every subsequent step wrong while looking perfectly reasonable.

The grown-up words

What it meansWhat it is calledNote
f(a) = 0 means (x − a) is a factorfactor theoremTry factors of the constant term
f(a) is the remainder on dividing by (x − a)remainder theoremFactor theorem is the zero case
Highest power of xdegreeA cubic has degree 3
Value that makes the polynomial zerorootCorresponds to a factor
Dividing one polynomial by anotherlong divisionOr compare coefficients

Check you have got it

Show that (x − 2) is a factor of x³ − 3x² + 4.
Substitute x = 2: 8 − 12 + 4 = 0. Since f(2) = 0, (x − 2) is a factor.
f(x) = x³ + 2x − 5. What is the remainder when divided by (x − 1)?
f(1) = 1 + 2 − 5 = −2, so the remainder is −2.
Edvia Free Resources · Additional Mathematics 4037 · Topic 3 — free to copy and share
Topic 4

Equations, inequalities and graphs

Sketching first turns most equation and inequality questions from algebra into reading a picture.

Picture itAsked to solve |2x − 1| < 5, most people start manipulating symbols and lose a sign. Sketch the V-shaped graph and a horizontal line at 5, and the answer is simply the bit of the V below the line — no sign errors possible.

Modulus equations split into two cases

|f(x)| = k means f(x) = k or f(x) = −k. Solve both, then check both answers in the original — squaring or splitting can produce solutions that do not actually work.

Modulus graphs bounce off the axis

The graph of y = |f(x)| is the graph of f with everything below the x-axis reflected upwards. Sketch f first, lightly, then flip the negative part. The corners are where f crossed the axis.

Inequalities need a sketch or a sign check

Find the critical values where the expression is zero or undefined, mark them on a number line, then test a point in each interval. Never multiply an inequality by something that might be negative without splitting into cases — it flips the sign.

Cubic and reciprocal graphs have recognisable shapes

Know what y = x³, y = 1/x and y = |x| look like before you plot anything. Most graph questions are transformations of a shape you already know, and recognising the parent shape saves the whole question.

The bit that catches people outWhen you multiply or divide an inequality by a negative number, the inequality sign reverses. −2x > 6 becomes x < −3, not x > −3. This is the single most common error in the topic and it is entirely avoidable by pausing whenever a negative appears.

The grown-up words

What it meansWhat it is calledNote
Size ignoring signmodulusSplits into two cases
Values where the expression is zero or undefinedcritical valuesMark them on a number line
Sign flips on multiplying by a negativeinequality ruleThe classic trap
Rough drawing showing shape and key pointssketchNot a plotted graph
The basic shape before transformationsparent graphx², x³, 1/x, |x|

Check you have got it

Solve |x − 4| = 3.
x − 4 = 3 gives x = 7; x − 4 = −3 gives x = 1. Both check out.
Solve −3x ≥ 12.
Divide by −3 and flip the sign: x ≤ −4.
Edvia Free Resources · Additional Mathematics 4037 · Topic 4 — free to copy and share
Topic 5

Simultaneous equations

Two equations, two unknowns — and when one of them is a curve, the answers tell you where a line meets it.

Picture itSolving a linear and a quadratic simultaneously is the same question as asking where a straight line crosses a parabola. Two solutions means it cuts twice, one means it is a tangent, none means it misses entirely.

Linear pairs: eliminate or substitute

Elimination when the coefficients match up neatly — multiply one equation through and add or subtract. Substitution when one equation is already arranged for a single letter. Both work; pick the one with less arithmetic.

One linear, one quadratic: always substitute

Rearrange the linear equation for one letter and put it into the quadratic. You get a quadratic in one variable, which you solve normally. Then substitute back to find the partner values — and remember each solution comes as a pair.

The number of solutions has a meaning

Two solutions: the line cuts the curve twice. One repeated solution: the line is a tangent. No real solutions: they never meet. Questions asking 'for what value of k is the line a tangent' are discriminant questions in disguise.

Always give answers in pairs

If x = 2 and x = 5, you must find the matching y for each. Writing four separate numbers with no pairing loses marks even when all four are correct.

The bit that catches people outSubstitute back into the linear equation, not the quadratic. It is simpler, and substituting into the quadratic can introduce a spurious partner value that does not satisfy both equations.

The grown-up words

What it meansWhat it is calledNote
Adding or subtracting to remove a lettereliminationMatch coefficients first
Replacing one letter with an expressionsubstitutionBest with a curve involved
Line touching a curve oncetangentRepeated root, discriminant zero
Where two graphs meetpoint of intersectionThe simultaneous solution
Answers that belong togethersolution pairEach x with its own y

Check you have got it

Solve y = x + 1 and y = x² − 1 simultaneously.
x + 1 = x² − 1 → x² − x − 2 = 0 → (x−2)(x+1) = 0 → x = 2 or −1, giving (2, 3) and (−1, 0).
A line meets a curve at exactly one point. What does that tell you about the resulting quadratic?
Its discriminant is zero — there is a repeated root, so the line is a tangent.
Edvia Free Resources · Additional Mathematics 4037 · Topic 5 — free to copy and share
Topic 6

Logarithmic and exponential functions

A logarithm answers the question 'what power do I need?' — and it is the tool that turns curves into straight lines.

Picture itEarthquake magnitude, sound in decibels and pH are all logarithmic scales. A magnitude 7 quake is not slightly worse than a 6 — it releases about thirty times more energy. Logs exist because some quantities span ranges too vast for ordinary numbers.

Logs and powers are the same statement

log_a b = c means exactly a^c = b. Every log question is a power question rewritten. If you get stuck, convert to power form and the way forward usually becomes obvious.

Three rules do all the manipulation

log a + log b = log(ab) · log a − log b = log(a/b) · log(aⁿ) = n log a. That third one is the workhorse: it brings a power down to the front, which is how you solve equations with the unknown in the exponent.

Solving 2ˣ = 20

Take logs of both sides: x log 2 = log 20, so x = log 20 ÷ log 2 ≈ 4.32. Any equation with x in the power is solved this way.

e and ln are just a particular base

e ≈ 2.718 turns up naturally in growth and decay. ln means log to base e. All the same rules apply — there is nothing special to learn beyond the notation.

Logs straighten exponential graphs

If y = kxⁿ, then log y = n log x + log k, so plotting log y against log x gives a straight line of gradient n. If y = kaˣ, plotting log y against x gives a straight line. This is the main reason logs appear in practical work.

The bit that catches people outYou cannot take the log of a negative number or of zero. When you solve a log equation, always check your answers back in the original — solutions that make any log's argument zero or negative must be rejected, and questions expect you to say so explicitly.

The grown-up words

What it meansWhat it is calledNote
The power you need to raise the base tologarithmlog_a b = c means a^c = b
log a + log blog(ab)Adding logs multiplies
log(aⁿ) = n log apower ruleBrings the power down
Log to base enatural logarithm (ln)e ≈ 2.718
Turning a curve into a straight linelinearisingPlot log y against log x or x
Answers that must be discardedrejected solutionsLog of a negative or zero

Check you have got it

Solve 3ˣ = 50, to 3 significant figures.
x = log 50 ÷ log 3 = 3.56.
You suspect y = kxⁿ. What do you plot to test it, and what does the gradient give you?
Plot log y against log x. A straight line confirms it, and the gradient is n.
Edvia Free Resources · Additional Mathematics 4037 · Topic 6 — free to copy and share
Topic 7

Straight-line graphs

Any relationship can be tested by rearranging it into y = mx + c — and then a straight line proves it.

Picture itSuppose you think two quantities follow a square law. Plot them raw and you get a curve, which could be almost anything. Plot one against the square of the other and if you get a straight line, you have proved it — and the gradient hands you the constant.

Everything reduces to y = mx + c

Whatever the relationship, the exam wants you to manipulate it until it looks like this. Then whatever multiplies the horizontal variable is the gradient, and whatever is left over is the intercept.

Choosing what to plot is the real question

For y = ax² + b, plot y against x² — gradient a, intercept b. For y = a/x + b, plot y against 1/x. For y = axⁿ, take logs and plot log y against log x. Identify the two things that go on the axes before doing any arithmetic.

Reading the constants off

Once you have a straight line, gradient and intercept give you the unknown constants directly. Draw a gradient triangle spanning at least half the line — small triangles magnify reading errors.

Why this matters beyond the exam

A straight line is the only graph the human eye can judge reliably. We are poor at telling a curve from a slightly different curve, but we can spot a bend in a straight line immediately. That is the entire reason this technique exists.

The bit that catches people outLabel the axes with what you are actually plotting, not the original variables. If you are plotting y against x², the horizontal axis is labelled x², not x. Mislabelling it makes the gradient meaningless and examiners mark it as such.

The grown-up words

What it meansWhat it is calledNote
y = mx + cstraight-line formThe target of every rearrangement
What multiplies the horizontal variablegradientGives one unknown constant
Where the line crosses the vertical axisinterceptGives the other constant
Rearranging into straight-line formlinearisingChoose the axes carefully
Triangle used to measure steepnessgradient triangleSpan at least half the line

Check you have got it

You think y = ax³ + b. What should you plot, and what do the gradient and intercept give?
Plot y against x³. The gradient is a and the vertical intercept is b.
For y = kxⁿ, what do you plot and why?
log y against log x, because taking logs gives log y = n log x + log k — a straight line of gradient n.
Edvia Free Resources · Additional Mathematics 4037 · Topic 7 — free to copy and share
Topic 8

Coordinate geometry of the circle

A circle is every point a fixed distance from a centre — and that one sentence, written algebraically, is the entire equation.

Picture itThe equation (x−3)² + (y+2)² = 25 looks abstract until you read it as Pythagoras: the horizontal distance squared plus the vertical distance squared equals 5². It is the distance formula, rearranged.

The standard equation

(x − a)² + (y − b)² = r², with centre (a, b) and radius r. Watch the signs — a centre at (3, −2) gives (x − 3)² + (y + 2)², because subtracting a negative adds.

Expanded form needs completing the square

If you are given x² + y² + 2gx + 2fy + c = 0, complete the square on the x terms and the y terms separately to get back to standard form and read off the centre and radius.

Tangents meet radii at right angles

That single fact solves most circle questions. To find a tangent at a point: find the gradient of the radius to that point, take the negative reciprocal, and use the point to get the equation.

Intersections tell you the geometry

Substitute a line into the circle's equation to get a quadratic. Two solutions means the line is a chord; one repeated solution means it is a tangent; none means it misses. Same discriminant logic as everywhere else.

The bit that catches people outWhen completing the square to find a circle's centre, remember the constant moves to the other side. From x² − 6x + y² + 4y − 12 = 0 you get (x−3)² + (y+2)² = 12 + 9 + 4 = 25, so r = 5, not √12. Forgetting to add the correction terms is the standard error.

The grown-up words

What it meansWhat it is calledNote
(x − a)² + (y − b)² = r²equation of a circleCentre (a, b), radius r
Line touching the circle at one pointtangentPerpendicular to the radius
Line cutting the circle at two pointschordQuadratic has two roots
Chord through the centrediameterTwice the radius
Rewriting to find the centrecompleting the squareRemember to adjust the constant

Check you have got it

Find the centre and radius of (x + 1)² + (y − 4)² = 9.
Centre (−1, 4), radius 3.
Why is the tangent to a circle perpendicular to the radius at that point?
Because the shortest distance from the centre to the tangent line is the radius, and the shortest distance is always along a perpendicular.
Edvia Free Resources · Additional Mathematics 4037 · Topic 8 — free to copy and share
Topic 9

Circular measure

Measuring angles in radians instead of degrees makes arc length and sector area almost trivial.

Picture itWhy invent a new angle unit? Because in radians, arc length is simply rθ. In degrees you need a fraction of 360 and a π every time. Radians were chosen to make the formulas disappear.

What a radian is

The angle where the arc length equals the radius. Since the whole circumference is 2πr, a full turn is 2π radians. So π radians = 180°, and that single conversion handles everything.

Two formulas, and both are clean

Arc length s = rθ. Sector area A = ½r²θ. Both require θ in radians. Compare that with the degree versions, which need θ/360 fractions, and the appeal is obvious.

Segments need a subtraction

A segment is the region between a chord and the arc. Find it as the sector area minus the triangle area: ½r²θ − ½r² sin θ. Nearly every segment question is this one line.

Common angles worth memorising

π/6 = 30°, π/4 = 45°, π/3 = 60°, π/2 = 90°, π = 180°. Recognising these instantly saves conversion time and reduces calculator errors.

The bit that catches people outBoth formulas only work in radians. If the question gives degrees, convert first — multiply by π/180. Using s = rθ with θ in degrees gives an answer that is wrong by a factor of about 57, and it is a very common way to lose a whole question.

The grown-up words

What it meansWhat it is calledNote
Angle where arc = radiusradian2π in a full circle
s = rθarc lengthθ must be in radians
A = ½r²θsector areaθ must be in radians
Region between a chord and an arcsegmentSector minus triangle
Multiply by π/180degrees to radiansAnd 180/π to go back

Check you have got it

A sector has radius 6 cm and angle 0.5 radians. Find its arc length and area.
s = rθ = 3 cm. A = ½r²θ = ½ × 36 × 0.5 = 9 cm².
Convert 135° to radians.
135 × π/180 = 3π/4.
Edvia Free Resources · Additional Mathematics 4037 · Topic 9 — free to copy and share
Topic 10

Trigonometry

Trigonometric functions repeat forever — and that periodicity is why one equation has infinitely many solutions.

Picture itAsk 'what angle has a sine of 0.5?' and your calculator says 30°. It is not lying, but it is only telling you one of infinitely many answers — 150°, 390°, 510° and so on all work too. The calculator gives you one; the question usually wants all of them in a range.

The three graphs and their shapes

sin and cos wave between −1 and 1 with period 360°, cos being sin shifted 90° left. tan repeats every 180° and shoots off to infinity at 90°, 270° and so on. Sketching the graph is the reliable way to find every solution.

Identities you must know

sin²θ + cos²θ = 1 and tan θ = sin θ / cos θ. Nearly every 'prove that' question uses one of these. If you are stuck, try converting everything to sines and cosines.

Finding all solutions in a range

Get the principal value from your calculator, then use the graph's symmetry to find the others in the given interval. Always check how many you should expect — a sine equation usually has two per 360°.

Reciprocal functions

cosec = 1/sin, sec = 1/cos, cot = 1/tan. Note that sec pairs with cos, not with sin — the naming is deliberately unhelpful and worth memorising directly.

Transformed graphs

y = a sin(bx) + c has amplitude a, period 360°/b, and is shifted up by c. Reading these off a given graph is a standard question.

The bit that catches people outYour calculator gives you one answer. The question almost always asks for all solutions in a stated range, such as 0° ≤ x ≤ 360°. Sketch the graph, draw the horizontal line, and count the crossings — that tells you how many answers you are looking for before you find them.

The grown-up words

What it meansWhat it is calledNote
Repeats every 360°sine and cosineAmplitude 1
Repeats every 180°tangentUndefined at 90°, 270°
sin²θ + cos²θ = 1Pythagorean identityThe most used identity
1/sin, 1/cos, 1/tancosec, sec, cotsec goes with cos
How far the wave goes from the middleamplitudeThe a in a sin(bx)
Length of one full cycleperiod360°/b

Check you have got it

Solve sin x = 0.5 for 0° ≤ x ≤ 360°.
x = 30° and x = 150°. The sine graph is symmetric about 90°, giving a second solution.
What is the period of y = cos(3x)?
360° ÷ 3 = 120°.
Edvia Free Resources · Additional Mathematics 4037 · Topic 10 — free to copy and share
Topic 11

Permutations and combinations

Counting arrangements when the numbers are too big to list — and the whole topic turns on one question: does order matter?

Picture itA three-digit padlock has 1,000 combinations. A three-card poker hand from 52 cards has 22,100. Both feel like 'choosing three things', but one cares about order and one does not — and that single difference changes the maths entirely.

Ask the order question first

If rearranging gives a genuinely different outcome, it is a permutation. If it is the same outcome either way, it is a combination. Deciding this before you reach for a formula is most of the work.

The formulas

Permutations: ⁿPᵣ = n!/(n−r)!. Combinations: ⁿCᵣ = n!/[r!(n−r)!]. The extra r! in the denominator divides out the orderings you do not want to count separately.

Factorial is just a descending product

5! = 5 × 4 × 3 × 2 × 1 = 120. And 0! = 1 — which looks strange but is needed for the formulas to work when r = n.

Restrictions are handled by dealing with them first

'How many arrangements with the two girls together?' — treat them as one block, arrange everything, then multiply by the arrangements within the block. 'Must start with a vowel?' — fix that position first, then arrange the rest.

The bit that catches people outA padlock 'combination' is a permutation — 1-2-3 does not open a lock set to 3-2-1. The everyday word is the mathematical opposite of what it describes, and that mismatch trips people up constantly.

The grown-up words

What it meansWhat it is calledNote
Order matterspermutationⁿPᵣ = n!/(n−r)!
Order does not mattercombinationⁿCᵣ = n!/[r!(n−r)!]
n × (n−1) × … × 1factorial0! = 1
Items that must stay togetherblockTreat as one, then arrange inside
Selecting without regard to orderchoosingUse ⁿCᵣ

Check you have got it

How many ways can 3 people be chosen from 8 for a committee?
Order does not matter, so ⁸C₃ = 56.
How many 3-letter arrangements can be made from 8 different letters?
Order matters, so ⁸P₃ = 336.
Edvia Free Resources · Additional Mathematics 4037 · Topic 11 — free to copy and share
Topic 12

Series

A series adds up a pattern — and if the pattern is regular enough, you can total a thousand terms without adding them.

Picture itThe story goes that a schoolboy Gauss was told to add every number from 1 to 100. He noticed 1+100, 2+99 and 3+98 all make 101, spotted there were fifty such pairs, and answered 5,050 almost immediately. That trick is the arithmetic series formula.

Arithmetic: add the same each time

Common difference d. The nth term is a + (n−1)d. The sum is Sₙ = n/2 [2a + (n−1)d], which is really just 'number of terms × average of first and last'.

Geometric: multiply by the same each time

Common ratio r. The nth term is arⁿ⁻¹. The sum is Sₙ = a(1 − rⁿ)/(1 − r). Growth and decay problems are almost always geometric.

Infinite geometric series can have a finite total

Only if |r| < 1, so the terms shrink towards zero. Then S∞ = a/(1 − r). If |r| ≥ 1 the terms do not shrink and the sum has no limit — and questions expect you to state that condition.

Binomial expansion

(1 + x)ⁿ expands using binomial coefficients, which are the ⁿCᵣ values from the previous topic. For a specific term, use the general term rather than expanding everything — much faster and far less error-prone.

The bit that catches people outCheck whether a sequence is arithmetic or geometric before choosing a formula. Arithmetic adds a constant; geometric multiplies by one. Test it: subtract consecutive terms, then divide consecutive terms. Whichever gives a constant tells you which it is.

The grown-up words

What it meansWhat it is calledNote
Same amount added each timearithmetic seriesCommon difference d
Same factor multiplied each timegeometric seriesCommon ratio r
a + (n−1)dnth term of an AP
a(1 − rⁿ)/(1 − r)sum of a GP
a/(1 − r), only if |r| < 1sum to infinityTerms must shrink
Expanding (1 + x)ⁿbinomial expansionCoefficients are ⁿCᵣ

Check you have got it

A geometric series has first term 8 and ratio 0.5. Find its sum to infinity.
S∞ = a/(1−r) = 8/0.5 = 16.
Why does a geometric series with r = 2 have no sum to infinity?
The terms grow rather than shrink, so the total increases without limit. A sum to infinity needs |r| < 1.
Edvia Free Resources · Additional Mathematics 4037 · Topic 12 — free to copy and share
Topic 13

Vectors in two dimensions

A vector carries both size and direction — which lets you describe movement and prove geometry without coordinates.

Picture itA plane flying at 800 km/h into a 100 km/h headwind travels at 700 km/h over the ground. Add the vectors and the answer appears. Add just the speeds and you get nonsense, because direction was carrying half the information.

Notation and the basics

Written as a column with x on top and y below, or in i and j form. Add vectors by adding components. Multiplying by a scalar stretches or shrinks it, and a negative scalar reverses its direction.

Magnitude is Pythagoras

The size of a vector is √(x² + y²). A unit vector has magnitude 1 and is found by dividing a vector by its own magnitude — useful when you want direction without size.

Position vectors locate points

The position vector of A is the vector from the origin to A. The vector from A to B is then b − a — destination minus start. Getting that order the right way round is essential.

Proving things with vectors

If one vector is a scalar multiple of another, the two are parallel. If they are parallel and share a common point, the points are collinear — they lie on one straight line. Almost every vector proof question uses one of these two facts.

Relative velocity

The velocity of A relative to B is v_A − v_B. Questions about closest approach or interception are usually asking you to work in the relative frame, where one object appears stationary.

The bit that catches people outThe vector from A to B is b − a, not a − b. Think of it as 'where you end minus where you start'. Reversing it points the vector the wrong way and every subsequent deduction inherits the error.

The grown-up words

What it meansWhat it is calledNote
Size and directionvectorColumn or i, j form
√(x² + y²)magnitudePythagoras on the components
Vector of magnitude 1unit vectorDivide by the magnitude
From the origin to a pointposition vector
One is a multiple of the otherparallel vectorsKey to most proofs
Points on one straight linecollinearParallel vectors sharing a point

Check you have got it

A has position vector (2, 1) and B has (7, 13). Find the vector AB and its magnitude.
AB = b − a = (5, 12). Magnitude = √(25 + 144) = 13.
How do you show three points are collinear using vectors?
Show that one vector between two of them is a scalar multiple of another, and that they share a common point.
Edvia Free Resources · Additional Mathematics 4037 · Topic 13 — free to copy and share
Topic 14

Calculus

Differentiation finds the rate of change; integration reverses it — and between them they solve almost anything about curves and motion.

Picture itA speedometer performs differentiation. It takes your position, which is changing, and reports how fast it is changing right now. An odometer performs integration — it takes your speed and accumulates it into total distance.

Differentiation: the gradient at a point

The derivative dy/dx gives the gradient of the curve at any x. Differentiate xⁿ by bringing the power to the front and reducing it by one: n xⁿ⁻¹. That single rule covers most of the syllabus.

Stationary points are where the gradient is zero

Set dy/dx = 0 and solve. Then use the second derivative to classify: if d²y/dx² is positive it is a minimum, if negative a maximum. Positive-minimum feels backwards to most people, so learn it deliberately.

The chain, product and quotient rules

For a function inside a function, use the chain rule: differentiate the outside, then multiply by the derivative of the inside. Use the product rule for things multiplied and the quotient rule for things divided. Identify the structure before choosing.

Integration: going backwards

Add one to the power and divide by the new power. Always add + c for an indefinite integral — and find c if you are given a point on the curve. For a definite integral, substitute the limits and subtract.

What integration gives you

The area under a curve between two limits. Also, in kinematics: differentiate displacement to get velocity and again for acceleration; integrate acceleration to get velocity and again for displacement. The whole chain runs both ways.

The bit that catches people outForgetting the + c on an indefinite integral is the most-penalised single error in calculus. It matters because infinitely many curves have the same gradient function — they differ only by a vertical shift, and c is that shift.

The grown-up words

What it meansWhat it is calledNote
Rate of change / gradient at a pointderivativedy/dx
Bring the power down, reduce by onedifferentiating xⁿn xⁿ⁻¹
Where the gradient is zerostationary pointMaximum, minimum or inflexion
Tells you max or minsecond derivativePositive = minimum
Function inside a functionchain ruleOutside, then times inside
Reverse of differentiationintegrationDo not forget + c
Area under a curve between limitsdefinite integralSubstitute and subtract

Check you have got it

Find the stationary point of y = x² − 6x + 5 and say whether it is a maximum or minimum.
dy/dx = 2x − 6 = 0 gives x = 3, y = −4. Second derivative is 2, which is positive, so it is a minimum.
A particle's velocity is v = 3t². How do you find the distance travelled between t = 0 and t = 2?
Integrate: ∫3t² dt = t³. Evaluate between the limits: 8 − 0 = 8 metres.
Edvia Free Resources · Additional Mathematics 4037 · Topic 14 — free to copy and share

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Every handout starts with the idea in plain English and only then the formal version. That is how every class at Edvia College works — for two full years of Cambridge A Levels.

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